Question:

Find the two values of k for which y(x) = e^{kx} ?

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is a solution of the differential equation y'' - 13 y' + 42 y=0

i need to find the smaller and larger value

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  1. k^2*e^kx-13k*e^kx++42e^kx=0

    k^2-13k+42=0    (k-6)(k-7)=0

    k=6  or   k=7

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