Find x-intercepts of y^2 = x^3 - 4x; show work?

Question

Find x-intercepts of y^2 = x^3 - 4x; show work?

Answer 1

the x intercept is when y = 0, so just plug in 0 for y and solve for x.

0 = x^3 -4x

x(x^2-4)=0

x (x-2)(x+2)=0

therefore x = 0, -2, 2

Answer 2

when y=0 u can find x intercepts

x^3 -4x =0

x(x^2-4)=0

x (x-2)(x+2)=0 by difference of 2 squares

but now we use the zero property

either x=0 or x-2=0 or x+2=0

this must be stated

therefore x =-2, 0,+2