Question:

Finding angular speed, degrees and angular acceleration?

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You are participating in league bowling with your friends. Time after time, you notice that your bowling ball rolls to you without slipping on the flat section of track. When the ball encounters the slope that brings it up to the ball return, it is moving at 3.91 m/s. The length of the sloped part of the track is 2.00 m. The radius of the bowling ball is 11.5 cm.

(a) What is the angular speed of the ball before it encounters the slope?

_____rad/s

(b) If the speed with which the ball emerges at the top of the incline is 0.40 m/s, what is the angle (assume constant) that the sloped section of the track makes with the horizontal?

_____°

(c) What is the magnitude of the angular acceleration of the ball while it is on the slope?

_____rad/s2

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  1. 1) Using V=R*OMEGA

                  3.91=11.5*omega-angular speed

                  3.91/11.5=omega

    0.34= angular speed

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