Finding the INTERCEPT and the ROOT?

Question

Hello!

I have a question where you are given the equation: 4x+3y+12=0

And the questions are:

a) Write y as a function of x

b) Then find the intercept and the root.

c) (Sketch a graph without graph paper), what is the slope of the graph of the function!

I will be very grateful to anyone who can help me with this!! Thanks :]

Answer 1

a)y=(-4/3)x-4

b)y intercept=-4

x intercept=-3

Answer 2

a) isolate y

3y = -4x - 12

y = -4/3x - 4

f(x) = -4/3x - 4

b) y-intercept is -4

root or x intercept:  

0 = -4/3 x -4

4 = -4/3 x

x = -3

c) slope is -4/3

all info is found by converting it into y=mx+b slope-intercept form of linear equation

hope this helps