Finding the Nth term of a sequence?

Question

Im in 8th grade Algebra its for high school credit. I need help finding the nth term of a sequence. For example:

4,7,10,13

For the 1st term I think this answer is 4+3(n-1) n=1

But how do i find the 2nd term. I know it would be 4+3(n-1) n=2

I just dont get how you get the answer. What does the (n-1) have to do with it. Also i need to know how to find the hundreth term of a sequence. Please help ASAP i got a test tomorrow.

Answer 1

Your first term:

4 + 3(1 - 1)

4 + 3(0)

4 + 0

4

Your second term:

4 + 3(2 - 1)

4 + 3(1)

4 + 3

7

etc.

The (n - 1) tells it what number to mutiply by 3 before adding 4.

So you already have the formula to find the n'th number:

4 + 3(n - 1)

If you want the 100th, plug in 100 and solve:

4 + 3(100 - 1)

4 + 3(99)

4 + 297

301

Answer 2

y = 3x +1

Eh, just came to me naturally.  =/

The hundredth term is

y(100)=3(100)+1=301

Answer 3

its a sequence. you have the equation right. all you have to do is plug in "n" into the equation to get your answer.

4+3(1-1)=4 for n=1

4+3(2-1)=7 for n=2

4+3(3-1)=10 for n=3

4+3(4-1)=13 for n=4

and just keep going on like that. you just plug it in.

make it a good day

Answer 4

Your nth term of the sequence is correct already. The sequence means that for the nth sequence, we need add the difference (n-1) times to the first number. For example, 7=4+(1*3)=4+((2-1)*3), 10=4+(2*3)=4((3-1)*3)

So, for nth sequence= 4+((n-1)*3), so for n=100, the 100th sequence is 4+(100-1)*3=4+(99*3)=4+297=301

Answer 5

You already have the formula and the 2nd term. :)  Just plug in the n value to find the terms you need.

4+3(n-1)

When n = 1 (that is, you're finding the first term):

4+3(1-1) = 4 + 3(0) = 4 + 0 = 4

When n = 2 (that is, you're finding the second term):

4+3(2-1) = 4 + 3(1) = 4 + 3 = 7

When n = 100 (that is, you're finding the hundredth term):

4+3(100-1) = 4 + 3(99) = 4 + 297 = 301