Finding the heat capacity of a calorimeter...?

Question

I have the equation:

m1cΔT1 = Cp(cal)ΔT2 + m2cΔT2

m1 = 10g

c = 4.184J x g^-1 x K^-1

ΔT1= 10°C

ΔT2 = 9.5°C

m2 = 10g

The equation I end up with is:

10g x (4.184J x g^-1 x k^-1) x 10°C = (Cp(cal) x 9.5°C) + 10g x (4.184J x g^-1 x k^-1) x 9.5°C

Do I need to convert my °C into K?

How do I find Cp(Cal)?????

Thank you!

Answer 1

Do I need to convert my °C into K?

No, because all they ask for is the change in Kelvin,

& changes in Celsius are equal to changes in Kelvin

=============================

How do I find Cp(Cal)?????

your equation so far is:

10g x (4.184J x g^-1 x k^-1) x 10°C = (Cp(cal) x 9.5°C) + 10g x (4.184J x g^-1 x k^-1) x 9.5°C

418.4 = Cp(cal) (9.5) & 397.48

Cp(cal) (9.5) = 418.4 -  397.48

Cp(cal) (9.5) = 20.92

Cp(cal)  = 20.92 / (9.5)

Cp(cal)  = 2.20 J/K

that's your answer