Finding the root of a function??

Question

Hello!!

I have the following equation: 2x-3y=6

I have put y as a function of x: y=2/3 x -3

The y-intercept: -2

But now I have to find the "root" or x-intercept? Could a kind person please outline how to do this? Thank you very much :]

Answer 1

If you want to find the x-intercept (a root) then you must let y = 0:

2x - 3y = 6

2x - 3(0) = 6

2x = 6

x = 3

Therefore, the root is at (3, 0).

To find the y-intercept let x = 0:

2x - 3y = 6

2(0) - 3y = 6

-3y = 6

y = -2

Therefore, the y-intercept is at (0, -2)

Now for your additional detail you would do the same:

1)  To find the x-intercept (a root) let y = 0.

2)  To find the y-intercept let x = 0.

Hope this helps!

Answer 2

to find the x-intercept put 0 in for y.

2x - 3y = 6

2x - 3(0) = 6

2x = 6

x = 3

(3, 0) = x-intercept