First order Ordinary Differential equation?

Question

Which of these is seperable?

(1/y)(dy/dx)=(2+x)y

or

(1/y)(dy/dx)=2y+x

also, for the seperable one, what is the general solution and what is the particular solution for y=1, x=0

Answer 1

(1/y)(dy/dx)=(2+x)y

(1/y²)dy=(2+x)dx

∫(1/y²)dy=∫(2+x)dx

-1/y+C1=2x+(1/2)x²+C2

-1/y=2x+(1/2)x²+C2-C1

let C2-C1=C

-1/y=2x+(1/2)x²+C

y=-1/(2x+(1/2)x²+C)

1=-1/(2*0+(1/2)*0²+C)

1=-1/C

C=-1

General solution: y=-1/(2x+(1/2)x²+C)

Particular solution: y=-1/(2x+(1/2)x²-1)