For heating a house in winter it requires 200MJ/h. The heat is supplied by a heat pump, which absorbs heat

Question

from cold air outside in winter to supply heat to the house. 30MJ/h is needed by the heat pump for its operation. Calculate the COP of heat pump. If the heat pump is used to cool the house during summer requiring 200MJ/h of heat rejection, calculate its COP.

Answer 1

For heating,

COP = (230 MJ/h) / (30 MJ/h) ≈ 7.67

For cooling,

COP = (170 MJ/h) / (30 MJ/h) ≈ 5.67