For the reaction Fe2O3(s) + 3CO2(g) = 2Fe(g) + 3CO2, 224g of CO is available to react with 400g of Fe2O3?

Question

wat is the limiting reagent??

hw mamy grams of iron is produced??

hw many grams of CO2 is produced??

Answer 1

The answer is exactly one metric ton of do your own Chemistry homework.

Answer 2

The molar ratio of iron 3 oxide to carbon MONOXIDE (I assume that is a typo) is 1:3. Given the masses of available reactants you need to determine the available mols of reactants. M (mols) = m (given in grams) divided by the molar mass of the reactant. In this case 400g Fe2O3 \ 159.7 g*mol^-1 gives about 2.5 mols of iron 3 oxide. Similarly 224 g CO2 \ 28.01 g*mol^-1 gives about 8.0 mols of carbon monoxide. If the ratio they react at is 1:3 mols iron 3 oxide to carbon monoxide, then 2.5 mols iron 3 oxide would require 2.5*3 mols, or 7.5 mols CO. 8.0 mols of CO are available, hence the Fe2O3 is the limiting reagent. 2.5 mols of Fe2O3 will react, and following the ratio of 1:2:3 for Fe2O3 to Fe to CO2 we get a total of 5.0 mols of Iron 3, and 7.5 mols of carbon dioxide. To find the masses of the products, we multiply the number of mols by the molar masses of the respective products. 5.0 mols Fe * 55.85 g per mol gives 279.25 grams of iron 3. 7.5 mols of CO2 * 44.01 g per mol gives 330.1 grams of carbon dioxide. In the question given the LEAST number of significant fiuges was the information 400g of iron 3 oxide. rounding our results to respect two significant figures we get about 280g of iron 3 and 330g of carbon dioxide, and of course the carbon monoxide is the limiting reagent. Hope this helps.

Answer 3

Here in wine and spirits you should investigate other kinds of reactions.

For example, try Oxidizing Alcohol into acid

CH3OH + CO  =  CH3COOH