For the reaction ............

Question

Cu(s) Ag (aq) -> Cu (aq) Ag(s)

is it:

Cu is reduced at the anodic and Ag is oxidized at the cathode?

Answer 1

Cu(s) +  Ag+(aq) -> Cu+(aq) + Ag(s)

Half-reactions:

At the cathode (where reduction takes place)-

Ag+(aq) + e- --> Ag(s)

At the anode (where oxidation takes place)

Cu(s) --> Cu+(aq) + e-

Therefore, Ag+ is reduced at the cathode and Cu(s) is oxidized at the anode.

[Answer: see above]