Question:

Formula for (1/2),(2/3),(3/4),(4/5)?

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What would be the formula to find this series of #'s: (1/2),(2/3),(3/4),(4/5)

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  1. n/(n+1)

    One answer's solution makes no sense.

    (3/4)+(1/6) is not (4/5)


  2. add 1 6th or 1/6

  3. n/(n + 1)
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