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Formula to find the force when the distance,time and mass is given?

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Formula to find the force when the distance,time and mass is given?

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  1. Use the 3 equations below to work out 3 variables, namely a = acceleration and v = final velocity.

    1. v = ut + 1/2at2

    2. v2 - u2 = 2as

    3. v = u + at

    First use 1 and 2 to work out t and u (simultaneous equations)

    Then use the other two equations to work out a.

    Then F = ma

    v = final velocity

    u = initial velocity

    t = time

    s = distance

    a = acceleration

    F = force

    m = mass


  2. Just remember that F=ma and you can't push on a rope.

    Everything else in mechanics will fall out with a bit of Calculus and some horse sense.

    Doug

  3. Force = (mass)(acceleration)

    Distance = .5(acceleration)(time^2) as long as  initial velocity is 0.

    so a = 2(d/t^2)

    so Force = 2(m * d)/(t^2)

  4. To find F, you need "a"

    In motion problems, you need any three of {dist, time, init vel., final vel, accel}

    Or, you can use F*t=change in momentum (but you need velocity change here).

    You don't have enough info, sorry.  (Unless we are to assume that the initial velocity was zero...in which case...

    dist = 1/2 a * t^2 gives you "a" and then F=ma gives you Force)

    Please give us the exact problem, if that is not what you were to assume.

    -Fred

  5. F=ma

    a=(v-u)/t

    v&u=d/t

    a=(d2-d1)/t

    F=ma=m*(d2-d1)/t

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