Four times the sum of r and s, increased by twice the diffference of r and s? is it 4(rs)+2(r-s)?

Question

Four times the sum of r and s, increased by twice the diffference of r and s? is it 4(rs)+2(r-s)?

Answer 1

four times the sume of r and s so the sum of r and s is r+s

so four times the sum is 4(r+s)

increased so 4(r+s)+ two times the difference of r and s

two times the difference of r and s.....2(r-s) so...

4(r+s)+2(r-s)

Answer 2

almost---the sum, so 4(r+s)+2(r-s).  good try.

Answer 3

<< four times the sum of r and s, >>

4(r + s)

<< increased by twice the diffference of r and s>>

4(r + s) + 2(r - s)

Hope this helps.

Answer 4

[4 (r+s)] + [2 (r-s)]

or 4r +4s +2r - 2s = 6r +2s

Answer 5

4(r+s)+2(r-s)

Answer 6

Your expression gives the sum of 4 times the product of r and s...  Make it the sum by the expression:

4(r + s) + 2(r - s)