Free fall acceleration?

Question

When stratled, an armadillo will leap upwards. Suppose it was 0.544m in the first 0.200s(a) What is its initial speed as it leaves the ground/(b) what is its speedat the height of 0.544m?(c) How much higher does it go?

Answer 1

Given:

at t = 0.200 s, d = 0.544m

Find:

a)  Vi, initial speed

b)  Vf, speed at height 0.544m

c)  h = Dmx - 0.544, how much higher it go

Solution:

a)  d = Vit + (1/2)gt^2

     0.544 = Vi(0.200) + (1/2)(-9.8)(0.200)^2

     Vi = [0.544 + (1/2)(9.8)(0.200)^2]/0.200

     Vi = 3.7 m/s    ANSWER

b)  Vf = Vi + gt

      Vf = 3.7 + (-9.8)(0.200)

      Vf = 1.74 m/s      ANSWER

c)   2gDmax = Vf^2 - Vi^2

           Dmax = (0^2 - 3.7^2)/(2)(-9.8)

           Dmax = 0.70 m

      h = Dmax - d

         = 0.698 m - 0.544 m

         = 0.154 m    ANSWER

Hope this helps.

teddy boy