Question:

Freezing Point?..................

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What is the freezing point of an aqueous 2.65 m calcium chloride (CaCl2) solution? The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºC/m.

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  1. I suggest to my students that they always start with the mathematical expression.

    DT = i k(f) m

    DT = 3 x 1.86 C/m x 2.65 m

    DT = 14.8 C

    The new freezing point is -14.8C


  2. This site might help you:

    http://en.wikipedia.org/wiki/Calcium_chl...

  3. 2.65 m calcium chloride (CaCl2)  turns lose triple that in ions = 7.95m

    7.95m @ 1.86 C / m = 14.8 C drop

    your answer is - 14.8C

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