Freezing point question?

Question

11. What mass of glucose (C6H12O6) must be dissolved in 1.0 L of water so that the solution has the same freezing point as a solution containing 10.0g of NaCl in 1.0 L of water?

Answer 1

you need to find how many moles of NaCl there are by dividing by its molar mass

for every mole of NaCl you need 2 moles of glucose

then you multiply the number of moles by molar mass of glucose

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Answer 2

freezing poing depression is directly proportional to the molality.

molality = moles / kg solvent

NaCl yields 2 moles of particles (Na+ and Cl-) per 1 mole of NaCl

10 g NaCl = 0.1711 mol and 0.3422 mol of particles.

You need 0.3422 mol of glucose.

0.3422 mol x 180.16 g/mol = 61.6 g glucose