Function f of g (I'm terrible with these...) f(x) = 1 - x^2 g(x) = 2x+1?

Question

Function f of g (I'm terrible with these...) f(x) = 1 - x^2 g(x) = 2x+1?

Answer 1

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Answer 2

f(g(x))= 1 - (2x +1)^2

= 1 - (4x^2 + 4x +1)

= 1 - 4x^2 - 4x -1

= -4x^2 - 4x    or -4 (x^2 + x )  or -4x (x + 1 )

hope this helps! : D

Answer 3

f(g(x))=1-(2x+1)^2

Answer 4

f of g means in f, replace x by g(x)

=> fog(x)

= 1 - [g(x)]^2

= 1 - (2x + 1)^2

= 1 - 4x^2 - 4x - 1

= - 4x(x + 1).

Answer 5

since

f(x)=1-x^2

if you want f(g(x)), replace x in the f(x) with g(x), which is 2x+1

so

f(g(x))=1-(2x+1)^2         (2x+1)*(2x+1)=(4x^2)+2x+2x+1=(4x^2)+4x+1

        =1-{(4x^2)+4x+1}

        =1-(4x^2)-4x-1

        =-(4x^2)-4x