GOOD AT MATH? HELP ME!!?

Question

The perimeter of a basketball court is 266 feet, and it's length is 35 feet more than it's width.What are the dimensions?

Answer 1

okay, first calm down. this is a pretty straightforward problem. If P = 266 feet, then you know the formula for calculating the perimeter right? P = 2L + 2W = 2(length) + 2(width). So if the length is 35 more than the width, then you know that L = 35 + W. So now plug it back into the original equation for the perimeter. So, P = 2(35 + W) + 2W = 266.

Solve for W, which is 49 feet. Since L = 35 + W, L = 84 feet

Answer 2

x +   X+35   + x    + x+35   so     4x + 70  =266    4x  =  266 -  70          so 4x =  196      divide  by 4     get x   then add 35  for length

Answer 3

266 = 2l + 2w

length = w + 35

therefore,

l = w + 35

and 266 = 2(w+35) + 2w

266 = 2w + 70 + 2w

266 = 4w + 70

196 = 4w

w = 49 feet

and because length = width + 35,

length = 49 + 35

= 84 feet

so width is 49 feet and length is 84 feet.

To check, 2l + 2w should equal 266.

2(84) + 2 (49) = 266

and it does.

Answer 4

Let x=the width, x+35= length

Perimeter: 2x+2(x+35)=266

                2x+2x+70=266

                       4x=196

                         x=49

                        x+35=84

                    84 by 49

Answer 5

length = 84ft

width = 49ft

Answer 6

Width (x):

2(x + x + 35) = 266

x + x + 35 = 133

2x = 98

x =  49

Length:

= 49 + 35

= 84

Answer: 49 by 84 feet is the dimension. The length, 84 feet, is 35 feet more than the width.

Checking perimeter of 266 feet:

= 2(49 feet) + 2(84 feet)

= 98 feet + 168 feet

= 266 feet