Galvanic Cells Help Please?

Question

If i have a galvanic cell

with 2 half cells

at the cathode: cu and cuso4 solution

at the anode: zn and znso4 solution.

if i increase the concentration of cuso4, and the anode half cell remains unchanged, i know that the voltage will increase, but why?

Answer 1

The voltage of a galvanic half cell is:

E=E0+(RT/zF)ln (Cox/Cred)  // Nernst equation

Cox is C(Cu2+) so if you increase the concentration of Cu2+ you increase the voltage of this half cell. While the voltage U of the other cell renain unchanged the difference E-U you determine will also increase.