Geometry? anyone good at it help me plz?

Question

plz help....

FIND THE PERIMETER OF EACH POLYGON

1. triangle PQR with vertices P(-6,-3), Q(1,-1), and R(1,-5)

2. pentagon ABCDE with vertices A(-6,2), B(-4,7), C(0,4), D(0,0) and E(-4,-3)

THANKS S0 MUCH!!! =]

Answer 1

Its not hard, but graph paper is good to have. I'm not sure i can do it w/o. It sounds 7th-8th grade question, but i dont have graph paper!

Answer 2

Egads.

1.You need to use the distance formula three times to find the length of each side of the triangle.

s1=√[(-6-1)²+(-3+1)²]

=√[(-7)²+(-2)²]

=√[49+4]

=√53

s2=√[(1-1)²+(-1+5)²]

=√[(0)²+(4)²]

=√16

=4

s3=√[(1+6)²+(-5+3)²]

=√[(7)²+(-2)²]

=√[49+4]

=√53

Perimeter =s1+s2+s3=√53+4+√53=4+2√53

2. You need to use the distance formula five times to find the length of each side of the pentagon.  How fun.

s1=√[(-6+4)² +(2-7)²]

=√[(-2)² + (-5)²]

=√[4+25]

=√29

s2=√[(-4-0)²+(7-4)²]

=√[(-4)²+(3)²]

=√[16+9]

=√25

=5

s3=√[(0-0)²+(4-0)²]

=√[(0)²+(4)²]

=√[0+16

=√16

=4

s4=√[(0+4)²+(0+3)²]

=√[(4)²+(3)²]

=√[16+9]

=√25

=5

s5=√[(-4+6)²+(-3-2)²]

=√[(2)²+(-5)²]

=√[4+25]

=√29

Perimeter is the sum of the sides, so √29+5+4+5+√29 or 14+2√29

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