Geometry help please!!?

Question

how do you do ..

2y^2 -8y + 5

directions say to factor.

thank you!

Answer 1

as it is u cant factor- did u copy it down right?>

but if u do: 2y^2 -8y - 5

(2y +2  )(y -5 ) gives -8y as the middle term-  

Answer 2

It does not appear to be factorable over the rationals..

Answer 3

( 2y-1) ( y-5)      

Answer 4

I believe you have to factor by completing the square. If that sounds familiar use this answer.

2y^2-8y+5

your y^2 can't have a constant in front of it so take out the two from the y's.

2(y^2-4y)+5

then you use the formula (b/2)^2   b being the second constant and add that inside the parenthesis and subtract that outside the paranthesis. 2(y^2-4y+4)-8+5 is what you should get. Remember you factored out a two so when you subtract (b/2)^2 you must multiply that by two. Now you have 2(y^2-4y+4)-3. which simplifies to 2(y-2)^2-3. this should be a reasonable ansewer.

Answer 5

y=8+{(8)^2-4(2)(5)}^1/2whole divided by 2.or

y=8-{(8)^2-4(2)(5)}^1/2whole divided by 2.

y=8+{64-40}^1/2whole divided by 2.or y=8-{64-40}^1/2.

y=8+{14}^1/2whole divided by 2.or y=8-{14}^1/2.