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Geometry question? easy 10 points?

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The base of an isosceles triangle is 15 inches. What is the smallest possible integer length for each leg?

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  1. 8+8=16

            16 > 15

    so each leg can be 8 in.

    you use the triangle inequality theorem


  2. In any triangle, the sum of two sides must be greater than the third.  Because it is isosceles, the legs must be the same lenght so: x + x > 15 --> 2x > 15, so divide both sides by 2, and x > 7.5.  therefore the smallest possible integer length for each leg is 8.

  3. Isosceles triangle= 2 sides same length

    The length of one side of a triangle cannot be greater than the sum of the lengths of the other sides.

    In short, x< y+z. X being any one side, y and z being the others.

    Let x= length of one side (not base)

    15< 2x

    7.5< x ---Divide both sides by 2.

    x> 7.5 ---Reflexive Property

    Since it says integer, the answer is 8 because 7.5 is rounded to 8.

  4. 8, I would think.  It will have to be at least a little longer than half of the base.

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