Give the calculation setup that shows...

Question

that if 10.0 mL of HCl (aq) requires 16.2 mL of 0.403 M NaOH in a titration, the molarity of the HCl is 0.653 M.

Answer 1

what?!?!? cant wait till chemistry :(

Answer 2

MaVa = MbVb

Ma is molarity of acid

Va is volume of acid

Mb is volume of base

Vb is volume of base

so  (Ma)*(10.0 mL) = (16.2 mL NaOH)*(0.403 M NaOH)

to solve for Ma it would be

Ma =  MbVb / Va