Question:

Given g(x)= -25+sqrtx+1 determine the inverse of g?

by Guest59997  |  earlier

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Given g(x)= -25+sqrtx+1 determine the inverse of g?

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  1. g(x) = sqrt(x - 1) -25

    let y = sqrt(x - 1) -25

    making 'x' the subject of the formula gives:

    y + 25 = sqrt(x - 1) and then

    (y + 25)^2 = x -1 and finally

    x = y^2 + 50y + 624

    giving inv of g(x) = x^2 +50x +624


  2. g(x)= -25+sqrt(x+1)

    y=-25+sqrt(x+1)

    switch y and x

    -25+sqrt(y+1)=x

    solve for y

    sqrt(y+1)=x+25

    y+1=(x+25)^2

    y=(x+25)^2-1

    g(-1)(x)=(x+25)^2-1

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