Gram Molecular mass?

Question

Each liqid in an experiment has an appreciable vapor pressure at room temperature. This means that at room temperature a significant portion of the sample is vaporized so that when the condensed vapor is weighed the flask contains sample plus air. The "empty" flask contained only air. The amount of air present during the last weighing is less than the amount of air in the "empty" flask because some of the air has been displaced by the vapor. Would this cause the exprimentally determined value of the gram molecular mass to be greater than, less than, or unchanged from the theoretical value? explain reasoning.

Answer 1

at the end of the experiment, the flask with condensed vapor  pulled in less air than it should, the total mass is  too light

when you subtract the "empty" flask with air ,... youi get an experimental mass of condensed vapor that is also too light

when youi get molar mass, by dividing the mass of vapor that is too light by the moles that come from PV=nRT calculations,  ....

your answer: that molar mass will also be too light