Grass, corn and sugar cane are all _________ of the angiosperms plants.

Question

Assume that a normal male and a female carrier of color blindness have four children: two sons and two daughters. ALL FOUR HAVE DIFFERENT GENOTYPES. The first son has normal color vision, the second son is color-blinded. The third child is a daughter and has normal color vision, but the fourth girl child is a carrier. What is the genotype of the first son, second son, the normal daughter, and the carrier daughter for color blindness? Use the the Key: A = normal color vision and dominant, a = color blind and recessive. These genes for color blindness are located on the X s*x chromosome. Y is equal to the Y chromosome.

Answer 1

For the first question:  Possibly C4 examples?

Second question:

Male parent = X(A)Y

Female parent = X(A)X(a)

Children:

son with normal vision = X(A)Y

son with color blindness = X(a)Y

normal daughter = X(A)X(A)

carrier daughter = X(A)X(a)

Answer 2

1st son: AA

2nd son: aa

normal daughter: AA

carrier daughter: Aa