Question:

H2(g) ZnO(s) = H2O(g) Zn(s)

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(f) Calculate the value of ∆Go for the reaction.

(g) Is the reaction predicted to be spontaneous under standard conditions at 25 degrees Celsius?

(h) Is the equilibrium constant for the reaction greater than 1 or less than 1?

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  1. ....H2(g)  &   ZnO(s) =>   H2O(g)   &   Zn(s)

    dGf: O   &  -318.2 -->  -->  -228.57   &   0

    dG = prod - reactants

    dG = -228.57 - (-318.2)

    your answer is dG = + 89.6 kJ

    ==================================

    because dG = "+" ..

    your answer it is not spontaneous

    ==========================

    because the products are not favored,

    yuor answer is: the K is less than 1

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