Question:

HARD Logarithm equation ?

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how would i solve for x in this equation

sqrt (x) = 1 + ln (2+x)

(sqrt is square root)

it tried to natural log both sides but it just won't simplify out! question been nagging me for long time

any other ways to solve for x , pls help

thanks in advance

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3 ANSWERS


  1. √(x) = 1 + ln (2+x)

    remember that ln e = 1

    √(x) = ln e + ln (2+x)

    √(x) = ln e(2+x)

    square both sides

    x = ln 2e(2+x)

    take e to power each side

    e^x = 2e(2+x)

    e^x = 4e + 2ex

    here I get stuck, later perhaps.

    .


  2. sqrt (x) = 1 + ln (2+x)

    the numeric answer is 14.44

    But to solve with algebra is something else...


  3. That equation is called transcendental, and can not be solved using algebra.  You might try graphing both sides, ie y=sqrt(x) and y=1+ln(2+x) and see if and where they intersect.  

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