HARD MATH QUESTION!! (to tough 4 u?)?

Question

Frank has $41 to spend on computer disks. A pack of 10 ES brand costs $13 and a pack of 11 CW brand costs $14. How many packs of each can he buy if he spends all his money?

(show work plz =D)

Answer 1

With $41, start by dividing it by the lesser cost brand @$13 which will give you 3+ packs and that should be the maximum limit. With $14, you can have 2+ packs and that would be the lower limit.

Within three packs for a total $41, and trying simple combination easily 2 packs for $14 and a pack for $13 would be determined.

Answer: 2 packs @$14=$28 & 1 pack @$13=$13; Total=$41.

Answer 2

x - the number of 10 ES

y - the number of 11CW

Then 13x + 14y = 41

x and y are natural numbers so you can easily replace them

You have to try all this cases.

1) if x = 0

then 14y=41 so y isn't natural

2) if x = 1

then 13+14y=41

14y=28

y=2 this is natural

You can go on searching for another good cases, but I don't think that there are any others.

3) if x=2

26 + 14y = 41

14y=15

y=15/14 isn't natural

4) if x=3

39+14y=41

y=2/14 isn't natural

5) if x=4

52+14y=41

52 > 41 so you can stop because y has to be positive.

The only good case is 2)

I helped you. Can you please help me too.

Go to http://www.tvblog.ro

Search: 'Serialul meu favorit'

And Click Prison Break.

Please.

Answer 3

a= 2 ($14) 1 ($13)

i did it in my head but, i'd say for showing your work:

41/3= 13 2/3

13 x 3= 36

14 x 3= 42      so.... 13+14+14= 41

Answer 4

d**n that is easy.

2*14=

1*13=

28+13=

Done.

You could've done that in less then half the time you spent writing the question.

Hope I got you thinking

Answer 5

Here's what the answer would look like without the attitude...

2*14=

1*13=

28+13= 41

Answer 6

You want us to do your homework? I'd rather say this and still get 2 points.

Answer 7

2 pack of CW & 1 pack of ES due to obvious reason.

28+13=41

Answer 8

41 = 13*ES + 14*CW

ES=1

CW=2