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HELP with titration?

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Given teh concentrated HCL is 12.1 M,how would you make 1.0 L of 1.0 M HCL?

*What is the molar concentration of 5.0 ml of hycloric acid that was titrated with 39.2 ml of 2.0 M NaOH?

I really need hel with this!

If someone can explain,it would be so great!

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  1. On the first one, for just dilutions you use the equation

    M1V1=M2V2 so

    (1M)(1L) = (12.1M)(xL), solve for x

    During a titration the moles of H= must equal the moles of OH= at the end point, so

    (0.0392L)(2M) = moles NaOH = moles OH-

    moles OH- = moles H+ = (0.005L)(xM)  solve for x

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