HELP!Algebra math problems , only high school peopel please or +?

Question

uhm read the title first.

just help me , give me the answers ,or teach me, anything.

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and show how u did it please.

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1)(c+d)to the power of 2; when c=2 and d=4.

2)7b to the power of 3,when b=3.

3)(5w)tot hte power of 2; when w=2.

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4)6x-2y / 5w

;when x=10,y=5,and w=5

HELP ME MORE ?

get at me at my yahoo messenger

which is forever21whateverloser

Answer 1

its hella easy.

okay

one would be

(2+4)2

so 2+4=6 to the 2nd power, it would be 36

i think thats how u do it anyway

2. 7*3=21 the the third power= 9261 (21*21*21)

3. 5*2=10 th the 2nd power=100 (10*10)

Answer 2

just remember ooo - pemdas [order of operation - parentheses, exponents, multiplication/division, addition/subtraction]

Answer 3

If that's too hard for you, you might need some tutoring to work on your math skills.  Talk to your parents about a tutor before you get too far behind.

Answer 4

i did this in 5th grade.... jeez... give me a break

Answer 5

first of all how do you not get this. i am going into 8th grade and i know this and i can do it in my head. so yeahh . you might need a tutor or something.  

Answer 6

Lol, high school people only. I could have done that in the 6th grade.

Answer 7

well since you already know what each variable is, substitute the numbers in first.

for the first one, you need to distribute.

(c+d)(c+d)=c^2+2cd+d^2

for the second, is it (7b) cubed or 7 times b cubed? if its the first one itll be 7b times 7b times 7b.if not itll be 7 times b times b times b.

third one: 25w^2.

fourth: plug in the numbers first and then simplify. so 60-10=50 divided by 25 which is 2.

and i agree with the other person. except you said you understand most of them but whatever.

Answer 8

just plug the letters in and solve

1) (c+d)^2

(2+4)^2

6^2

36

2)7b^3

7(3)^3

7(27)

189

3)(5w)^2

(5(2))^2

10^2

100

4)6x-2y/5w

6(10)-2(5)/5(5)

60-10/25

50/25

2

hope this helped!