HOMEWORK HELP?????!!!?

Question

Ok i really need help, cause I just don't get this one problem at all, I took a picture of the question, so if you would be so kindly as to look at it, and i took a picture of the diagram, but it's kinda unclear..

http://i270.photobucket.com/albums/jj85/pommy48/DSC01171-1.jpg

http://i270.photobucket.com/albums/jj85/pommy48/DSC01175.jpg

Answer 1

lol I know how you feel thats really confusing!

Answer 2

First off, we need to write all the given:

Note: Since there isn't a letter L in this problem, I'll be using the letter L as the symbol for angle.

mLAOB = mLAOC + mLBOC, mLAOC = mLBOC since OC is a bisector

mLAOC = mLAOD + mLCOD, mLAOD = mLCOD since OD is a bisector

mLAOD = mLAOE + mLDOE, mLAOE + mLDOE since OE is a bisector

mLAOE = mLAOF + mLEOF, mLAOF + mLEOF since OF is a bisector

mLCOF = mLFOG + mLCOG, mLFOG + mLCOG since OG is a bisector

Also, since we have equal measurements for some angles:

mLAOB = 2mLAOC or 2mLBOC

mLAOC or mLBOC = 2mLAOD or 2mLCOD

mLAOD or mLCOD = 2mLAOE or 2mLDOE

mLAOE or mLDOE = 2mLAOF or 2mLEOF

mLCOF or mLEOF = 2mLFOG or 2mLCOG

Now, we try to solve for the measures of each angle:

mLBOF = 120 (given)

mLBOF = mLBOC + mLCOD + mLDOE + mLEOF (taken from the diagram, I listed the parts of LBOF)

120 = mLBOC + mLCOD + mLDOE + mLEOF

Given from above:

mLBOC = 2mLCOD

mLDOE = 2mLEOF

Substituting with the values above, we get:

120 = 2mLCOD + mLCOD + 2mLEOF + mLEOF

120 = 3mLCOD + 3mLEOF (divide both sides by 3)

40 = mLCOD + mLEOF

Given from above:

mLCOD = 2mLDOE

Substituting that, we have:

40 = 2mLDOE + mLEOF

Given from above:

mLDOE = 2mLEOF

Substituting that, we have:

40 = 2(2mLEOF) + mLEOF

40 = 4mLEOF + mLEOF

40 = 5mLEOF

mLEOF = 8

Also:

mLAOF = 8

mLAOE or mLDOE = 16

mLAOD or mLCOD = 32

mLAOC or mLBOC = 64

mLAOB = 128

Next problem:

Given:

mLCOG = 35  So:

mLFOG = 35

mLDOE = 16

mLEOF = 8

mLFOD = mLDOE + mLEOF (refer to the diagram, I listed the parts)

mLFOD = 16 + 8

mLFOD = 24

mLFOG = mLFOD + mLDOG (refer to the diagram, I listed the parts)

Again, the given are:

mLFOG = 35

mLFOD = 24

Substituting that, we have:

35 = 24 + mLDOG

mLDOG = 11

To finally get mLEOG:

mLEOG = mLDOE + mLDOG

Given:

mLDOE = 16

mLDOG = 11

Substituting that, we have:

mLEOG = 16 + 11

mLEOG = 27

----> deep sigh of relief

I hope that helped! That was really long.. Oh yeah, don't forget to write the degree sings.. ^^,

Answer 3

I think there is a flaw in this problem. Here are some of the measures I got:

BOF = 120

COG = 35, so GOF = 35 because G bisects FOC = 70

AOC = 50, so COB = 50 because C bisects AOB and since BOF is 120, subtract FOC 70 = 50.

Since AOC and COB make AOB, then AOB = 100

All measures:

AOB = 100

AOC = 50 = COB = 50

AOD = 25 = DOC = 25

AOE = 12.5 = EOD = 12.5

AOF = AOB - BOF

Here's the conflict: 100 - 120 = -20 and a negative measure of an angle is impossible.

Anyway, since COG = 35 and COD = 25, then DOG = 10.

Then EOD - DOG = EOG, 12.5 - 10 = 2.5, so EOG = 2.5

Final answer DOE = 12.5 and EOG = 2.5.

Because of the issue finding AOF, I'm not sure if these answers are correct, but I worked your problem several ways and this is the most likely solution to finding the measures of DOE and EOG.

By the way, in order to work this problem, you need to work backward from the given amounts. I hope this is some help at least.

Answer 4

bof=120, then doe=?

2(aoc)=(aob)

4(aod)=(aob)

8(aoe)=(aob)

16(aof)=(aob)

15(aof)=(bof)

15(aof)=120

aof=8

2(aof)=doe

doe=16

heres the second part

cog=35, then eog=?

2(aod)=(aoc)

4(aoe)=(aoc)

8(aof)=(aoc)

2(cog)=(foc)

2(35)=(foc)=70

7(aof)=(foc)

7(aof)=70

(aof)=10

aof=foe

fog-foe=eog

35-10=25

eog=25

Answer 5

uhhh dont know math like that?? lol T.T sorries ask parents? ask friends? call all ur friends? ask em all? lol