HOW DO YOU DO THIS?!?!?!?

Question

The gas constant R (as in PV=nRT) 8.314m^3●Pa/mol●K. Also R= 8.314 J/mol●K. Therefore m^3●Pa equals 1 J. Using the fundamental SI units (m, kg, and s) demostrate that 1 m^3●Pa indeed equals 1 J.

I don't understand!! please explain!!!

Answer 1

In order to demonstrate this, set up an equation:

8.314 m^3 * Pa / mol*K = 8.314 J/mol*K

Now divide by 8.314:

1 m^3 * Pa / mol * K = 1 J / mol * K

Now multiply both sides by Kelvin (K):

1 m^3 * Pa / mol = 1 J / mol

Multiply both sides by Moles (mol):

1 m^3 * Pa = 1 J

And you've proven it!

Answer 2

is that your homework?! if it is, you're CHEATING!!!!!!!! learn to be INDEPENDENT

Answer 3

1Pa= 1N/1m^2 (1 newton by square meter)

if you multiply by 1m^3 you find 1N*1m^3/1m^2 = 1N*1m and this is one joule

Answer 4

Pa=N/m^2

m^3*Pa=m^3*N/m^2=mN=J