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Help! 7th grade advanced math question!?

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What is the sum, of the measures,of the angles of a 12 sided polygon. Hint: choose one vertice and create as many triangles as you can.

12 sided polygon http://etc.usf.edu/clipart/37300/37388/12-gon_37388_lg.gif

please help!

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  1. I will suggest another way of doing this problem. remember the sum of the exterior angles of any polygon no matter how many sides is 360.

    So a regular polygon has each exterior angle equal to 360/n, n is he number of sides. (I know your polygon is not a regular polygon but bear with me none-the-less.)

    If the polygon were regular each exterior angle would be 360/12 = 30. the interior angles would all be 180 - 30 = 150.

    150*12 = 1800.

    We can do it this way because the sum of the angles of a 12 sided polygon is ALWAYS the same.


  2. i dunno about making triangles, but there is a simple formula that will do this for you.

    180n-360=sum, where n is the number of sides

    180(12)-360=1800

    this is the sum, and if you want what every angle would be just divide that by twelve, or 150

    make it a good day

  3. I'm going to help you because you have your own teacher.

  4. Thankfully, there is a formula for this.

    The sum of the angles in any polygon with

    n-sides is: (n-2)(180)

    For a 12-sided polygon

    (12-2)(180) = (10)(180) = 1800

    1800 is the sum of all the angles.

    Here is what your teacher is saying...

    Take a square.

    Draw a diagonal on the square.

    This forms two triangles.

    Each triangle's angles have a sum of 180 degrees

    There are 2 triangles in the square, so the square's angles have a sum of 360 degrees.

    This is why the formula given above works.

    And if you're still reading, thanks for being patient and reading everything.

  5. The sum of the interior angles for any regular polygon is 180*number_of_sides - 360

    180*12-360 = 1800

  6. The sum of the measures of the angles of a polygon

    = (number of sides - 2) x 180

    Since our figure has 12 sides

    = (12 - 2) x 180

    = 10 x 180

    = 1800 degrees

    Hope this helps you!  Please email anytime for further questions.

  7. there is an easier way to think of this.

    pretend that the sides are stretchy.

    pick to verticies, and pull.

    what you end up with is 2 angles of 0 degrees, and 10 of 180 degrees.

    thus the formula  (n-2)*180

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