Help.......Factor completely?

Question

Factor completely: Make sure to superscript all exponents. If you believe that a polynomial is not factorable, label it as prime. Show all stages of factoring separately (i.e., show the result of factoring out a GCF before taking the resulting polynomial and factoring it again).

x^2 – 4xy + 12ax – 48ay

Answer 1

x^2 - 4xy + 12ax - 48ay

= (x^2 - 4xy) + (12ax - 48ay)

= x(x - 4y) + 12a(x - 4y)

= (x - 4y)(x + 12a)

Answer 2

x^2 – 4xy + 12ax – 48ay

LET US TAKE THE COMMON  IN SIDE

x(x-4y)+12a(x-4y)

(x+12a)(x-4y) ANSWER

GOOD LUCK

Answer 3

Factor the greatest common factor (GCF) from each group.

Group the first two terms together, and group the second two terms together.

(x^2 - 4xy) + (12ax - 48ay)

Factor the greatest common factor (GCF) from each group.

(x(x - 4y) + 12a(x -4y))

Factor the polynomial by grouping the first two terms together and finding the greatest common factor (GCF). Next, group the second two terms together and find the GCF. Since both groups contain the factor (x - 4y) they can be combined.

(x + 12a) (x - 4y)

Let's multiply the above using the FOIL Method:

x x x = x^2 (x times x equals x squared)

x x -4y = -4xy

12a x x = 12ax

12a x -4y = -48ay

Let us now add the above:

x^2 - 4xy + 12ax - 48ay

So the correct answer is:

(x + 12a) (x - 4y)

I hope the above explanations and steps have helped you to understand. Good luck in your pursuit of learning math (including algebra).

Answer 4

here mimi...

1st. factorise the first two terms

   x^2 - 4xy = x(x-4y)

2nd. factorise the last two terms

   12ax - 48ay = 12a(x - 4y)

then...

x^2 – 4xy + 12ax – 48ay

   x(x-4y)   +  12a(x - 4y)

      (x - 4y)(x+12a)

done.

Answer 5

x(x-4y)+12a(x-4y)

(x+12a)(x-4y)