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The number of semester credit hours for a sample of seven part-time college students is: 8, 5, 4, 10, 8, 3, and 4. Compute the:

a. mean b. median c. mode

Please help to answer this. I really have no idea about it. This question is rather easy for u all. I will provide BA.

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  1. Mean = average, add all up and divide by number in sample

    8+5+4+10+8+3+4/7 =  6

    Median = middle number, arrange in order from smallest to largest and find the middle number

    Order, 3,4,4,5,8,8,10  

    Middle = 4th in sequence = 5

    Mode = the number that occurs the most

    4 and 8 both occur twice


  2. lets think back to 5th grade...

    1st put the numbers in order...

    3, 4, 4, 5, 8, 8, 10

    2nd figure out what the terms mean, the compute...

    mean- average

    - to get the average first add up all the numbers to get 42 then divide that by the amount of numbers that are to be averaged, which would make 6. that's your mean

    median- the number in the middle

    - just pick out the number that is in the middle when they are in order, which, in this case, would be 5.

    mode- the number(s) that occur more most often, there can be more than one mode

    - you just use your eyes for this one, 4 and 8

  3. mean is 6

    median is 5

    mode is 4 and 8

  4. the mean is 6

    the median is 5

    and the mode is 4 and 8.

  5. The mean is the sum of all numbers divided by the number of numbers

    8 + 5 + 4 + 10 + 8 + 3 + 4 = 42

    42/7 = 6  which is the mean

    Order the numbers in ascending order

    3, 4, 4, 5, 8, 8, 10

    The median is the one in the middle of the list, which is 5, because there are three numbers smaller than 5 and three numbers bigger than 5

    The mode is the value that appears most often, since 4 and 8 each appear twice there are two modes 4 and 8

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