Question:

Help!!! Physics and Electric Potential!!

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A 3.0nC charge is at x=0 and a -1.0nc chrage is at x=4cm. At what point or points on the x-axis is the electric potential zero?

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1 ANSWERS


  1. Since F= k Qq/R^2

    then E=F/q

    q- arbitrary test charge

    F- force between a charge and a test charge q

    E- electric field at test charge q

    E total = F1/q + F2/q

    Et otal = k( Q1/ R1^2 + Q2/R2^2) =0

    Q1/ R1^2 + Q2/R2^2 =0  or

    Q1/ R1^2 = - Q2/R2^2

    Reducing to one unknown

    Let  

    R1= R+0

    R2= R+4

    Q1/R^2 = Q2/(R+4)^2 we have a quadratic equation

    Q1( R+4)^2= Q2R^2

    (Q1-Q2)R^2 + 8Q1R + 16=0

    Solve for R (Yes, two answers indeed)

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