Help!! Physics question! velocity and acceleration....?

Question

Suppose a stone is thrown from a building that is 45 meters high at an angle 22.0° below the horizontal. If it strikes the ground 34.3 m away, find the following values.

(a) time of flight

(b) initial speed

(c)speed and angle of the velocity vector with respect to the horizontal at impact

Answer 1

a)  45 = Vo*tsin22° + ½gt²;  34.3 = Vo*tcos22°;  Solve for t & Vo →

t = 5.58 sec and

b) Vo = 9.629 m/s

c)  Vv = √(2*g*h + (Vosin22°)²) = 29.802 m/s

Vh = Vocos22° = 6.146 m/s

Vf = √(Vv² + Vh²) = 30.429 m/s

Θ = arctan (29.802/6.146) = 78.35°