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Help! Please!? ?

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Here is a question from my homework that I don't really get how to do:

Suppose a sample of aluminum is placed in a 25mL graduated cylinder containing 10.5 mL of water. the level of the water rises to 13.5 mL. What is the mass of the aluminum sample?

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  1. Step 1: 13.5 ml minus 10.5 ml = 3 ml.  Therefore, the aluminum sample is has a volume of 3 ml

    Step 2: Find the specific gravity of aluminum from a table.  The site shown below shows that the specific gravity of AL is 2.6989.  I'll round this to 2.7.

    Step 3: Water has a mass of 1 gram per ml at standard temperature.  The specific gravity of AL is 2.7, so the mass of the AL in the cylinder is 3 times 2.7 grams, or 8.1 grams.


  2. If the water is displaced 3mL, then 3mL (or cubic centimeters) of aluminum have been placed in the graduated cylinder. Aluminum is about 2.7 g/mL, so 2.7 x 3 = 8.1

    The aluminum is 8.1grams

    If something sinks in a fluid, it will displace equal volume. However, if it were something which floats, remember that it would displace an equal MASS.

    Hope this helps.
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