Help due tomorrow math question easy?

Question

Pigs are $3 bucks each

Cows are $10 bucks each

Sheep are $o.50 each

I have 100 bucks

And have to have 100 animals

I cant figure it out its for a 7th grade girl

its due tomorrow

thx

Answer 1

i tryed...i wasnt successful..my brain is NOT working

Answer 2

Buy 80 Sheep = $40

Buy 20 Pigs = $60

Answer 3

Grrrrr Puzzling - I was about to post the same answer!

Puzzling's answer is correct.

Answer 4

3 PIGS=         $9.00

1 COW=        + $10.00

162 SHEEP=      $81.00

                -------

                $100.00

*not sure if its right but i hope it helps, good luck....

Answer 5

Let P be the number of pigs

Let C be the number of cows

Let S be the number of sheep

Cost:

3P + 10C + 0.50S = 100

Animals:

P + C + S + 100

You have two equations and 3 unknowns, so it looks unsolvable, but you can actually figure it out.

Start by multiplying the top equation by 2 to get rid of the fractional amount:

6P + 20C + S = 200

Subtract the second equation:

6P + 20C + S = 200

-(P + C + S) = -(100)

5P + 19C = 100

Now you have to try some numbers.  I would notice that all the values have to be integers, and none can be negative.  I also assume you need at least one of each type of animal:

Try 1 cow.

C = 1

5P + 19(1) = 100

5P = 81

P = 81/5

P = 16.2 pigs (nope!)

Try 2 cows:

C = 2

5P + 19(2) = 100

5P = 62

P = 12.4 pigs (nope!)

(Skipping some work because 3 and 4 cows will also result in a fractional amount of pigs...)

Try 5 cows:

C = 5

5P + 19(5) = 100

5P + 95 = 100

5P = 5

P = 1

This seems to work, so let's check it out:

P = 1

C = 5

S = 94

----------

100 animals

Cost:

1*$3 + 5*$10 + 94*$0.50

= $3 + $50 + $47

= $100

Assuming you need one of each animal the answer is:

1 pig ($3)

5 cows ($50)

94 sheep ($47)

(Note: technically 20 pigs, 0 cows and 80 sheep is another answer, but usually the question would be phrased saying you have to purchase at least one of each type of animal.)

Edit:  I see you added the requirement about needing at least one of each type, so the answer is definitely what I said.