Help >< please ! i need homework help so bad

Question

answer one or two or as many as you want, please please please i really need help, i'm desperate. if you could, show the process of how you did it.

add 4 to a number, the result is the same as multiplying that number by five. what is the number ?

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fifteen years later, tom will be twice as old as he is now. how old is he now ?

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if 101 is multiplied by 99, the answer is 9999. is it true ?

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the average of four numbers is 32. if the four numbers are increased by one, two, three and four respectively, what is the new average of the four numbers?

these are algebra questions.

Answer 1

1st answer is 1

2nd is 15

3rd is true

Answer 2

add 4 to a number, the result is the same as multiplying that number by five. what is the number ?

n + 4 = 5n

4 = 4n

1 = n

fifteen years later, tom will be twice as old as he is now. how old is he now ?

t + 15 = 2t

15 = t

if 101 is multiplied by 99, the answer is 9999. is it true

Yes

the average of four numbers is 32. if the four numbers are increased by one, two, three and four respectively, what is the new average of the four numbers?

(a + b + c + d)/4 = 32

(a + b + c + d) = 128

(a + 1 + b + 2 + c + 3 + d + 4) = 128 + 1 + 2 + 3 + 4

(a + 1 + b + 2 + c + 3 + d + 4) = 138

(a + 1 + b + 2 + c + 3 + d + 4)/4 = 138/4

(a + 1 + b + 2 + c + 3 + d + 4)/4 = 34.5

Answer 3

1. Add 4 to a number. The result is the same as multiplying that number by five. What is the number?

Let the number equal to &#039;n&#039;. &#039;Add 4 to a number&#039; written algebraically is &#039;n+4&#039;. &#039;The result is the same as multiplying that number by five&#039; written algebraically is &#039;n+4= 5n&#039;. So, we have:

n+4= 5n

4= 4n ---Subtract both sides by n.

1= n ---Divide both sides by 4.

n= 1 ---Reflexive property

Translate that back--- The number is 1.

2. Fifteen years later, Tom will be twice as old as he is now. How old is he now?

Let Tom&#039;s current age equal to &#039;n&#039;. &#039;Fifteen years later&#039; written algebraically is &#039;n+15&#039;. &#039;Tom will be twice as old as he is now&#039; written algebraically is &#039;2n&#039;. Combine those two and you get, &#039;n+15= 2n&#039;. So:

n+15= 2n

15= n ---Subtract both sides by n.

Tom is 15-years-old.

3. If 101 is multiplied by 99, the answer is 9999. Is it true?

Yes.

4. The average of four numbers is 32. If the four numbers are increased by one, two, three, and four, respectively, what is the new average of the four numbers?

You are given FOUR numbers. You know that the average of those four numbers is 32. 32 multiplied by 4 is 128. Ignore the increasing respectively part and think of it like this: an increase by 1, 2, 3, and 4 is a total increase of [1+2+3+4= ] 10. Therefore, 128+10= 138 and 138 divided by 4 is 34.5.

Answer 4

1)     x + 4 = 5x

        4 = 4x

        x = 1

2)     x +15 = 2x

        x = 15 yrs. old

3)     true

4)    34.5

Answer 5

1

let x be a number.

x+4 = 5x

4 = 5x - x (subtract x from each side)

4 = 4x (now divide by 4)

x=1

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15

x is tom&#039;s current age

x+15 = 2x

do the same thing as above

x = 15

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true

use a calculator or something lol

ok. 99 x 100 is 9900

now add on 99 x 1

so 9900+99 =???

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34.5

ok, if all 4 numbers are 32, the average will be 32.

now just add 1, 2, 3, and 4 so the new numbers are 33, 34, 35, 36.

Average them together (i hope you know how to do that)

hope that helps

Answer 6

Tom is 30 years old.

101 times 99 is 9999, so yes, it is true.