Question:

Help in biology please?

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In humans, widow's peak (W) is dominant over straight hairline (w) if a heterozygous male marries a female with a straight hairline what percent of their children can be expected to have a widow's peak?

A) 0%

B) 25%

C) 50%

D) 100%

E) Can't be determined

Thank you in advance for help with this!!!

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4 ANSWERS


  1. This can be solved easily with a Punnet Square.

    Step 1: Make a Key

    WW-Widows peak

    Ww- Widows peak

    ww- Straight hairline

    Step 2: Figure out the parents' gametes

    Hterozygous means 2 different (W and w) so the male has to have a W and w The female's gametes are ww since she has a straight hairline.

    Step 3- Make a box out of 4 little squares and draw the sperm on top Ww. The eggs are on the side ww.

    Step 4- match the letters up in each box.

    You can expect 50% to have a widow's peak


  2. C) 50%

    hope i helped

  3. The father is heterozygous with a widow's peak:  Ww

    The mother has a straight hairline: ww

    Ww x ww

    Make a punnett square and the offspring will be:

    50% Ww and 50% ww

    so the answer is c) 50% of the offspring can be expected to have a widow's peak

  4. C) 50%

    Parents are Ww & ww gives possible offspring Ww, Ww, ww, ww.(50:50)

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