Help me pre algebra please!!!??!?!?!?!?!?

Question

help me with this problem please!!

Tania found a sale on the store. She bought 2 pairs of shorts and 3 pairs of socks for $33. Keisha bought 1 pair of shorts and 5 pairs of socks for $27. HOW MUCH DID EACH ITEM COST????

HELP PLEASE THANK YOU!!

Answer 1

(this girl) is loco

Answer 2

Let x = cost of a pair of shorts

.....y = cost of a pair of socks

"2 pairs of shorts and 3 pairs of socks for $33"

2x + 3y = 33

"1 pair of shorts and 5 pairs of socks for $27"

x + 5y = 27

system of equations:

2x + 3y = 33

x + 5y = 27

I will use the elimination method. Multiply second equation by -2.

The system of equations becomes:

2x + 3y = 33

-2x - 10y = -54

----------------------

........-7y = -21

..........y = 3

Plug in 3 for "y" in one of th equations and find "x".

x + 5y = 27

x = 27-5y = 27-5(3) = 27-15

x = 12

Shorts cost $12 per pair and socks costs $3 per pair.

check:

2x + 3y = 33

2x+3y = 2(12)+3(3) = 24+9 = 33

Answer 3

Let:

h = cost of a pair of shorts

s = cost of a pair of socks

We're told that 2 shorts and 3 socks costs 33, so:

2h + 3s = 33

And also that 1 shorts and 5 socks cost 27, so:

h + 5s = 27

we have two unknowns and two equations . solve .. I'll set h in terms of s in the 2nd equation, then plug into first equation to solve for s.

h + 5s = 27

h = 27 - 5s

2h + 3s = 33

2(27 - 5s) + 3s = 33

54 - 10s + 3s = 33

-7s = -21

s = 3

Now solve for h, plug this into either equation above:

h = 27 - 5s

h = 27 - 5(3)

h = 27 - 15

h = 12

Each pair of shorts cost $12.  Each pair of socks cost $3.

Answer 4

let x=shorts

y=socks

2x + 3y = 33

1x + 5y = 27

Answer 5

x = shorts

y = socks

2x + 3y = 33

x + 5y = 27

-2x -10y = -54

-7y = -21

y = 3 = price of socks in dollars

x = (33-9)/2 = 12 = price of shorts in dollars