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500 mL of 9 M Sulfuric Acid (H2SO4) is combined with 750 mL of 6 M Barium Hydroxide (Ba(OH)2 producing Barium Sulfate (BaSO4) and water. What mass of Barium Sulfate will be produced. (assume 100% yield)

2. Which of the following must be true if a solution is to be considered an acid:[H+] > [OH-]?[H+] < [OH-]?[H+]= [OH-]?Kw = [H+]/[OH-]

3. A base will usually contain:

The Hydroxide Ion (OH)

Hydrogen

Ammonia

None of the above.

4. Which of the following is a conjugate acid-base pair?HCl/OCl-?H2SO4/SO4(2-)?HCl, Cl-?H3O+/OH-?. the first one?

5. How does the H+ ion concentration of a solution that has a ph of 3 compare with the H+ ion concentration of a solution with a ph of 6.

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  1. Moles H2SO4 = 0.500 L x 9 M =4.5

    moles Ba(OH)2 = 0.750 L x 6 M =4.5

    we will get 4.5 moles of BaSO4

    mass BaSO4 = 4.5 x 233.43 g/mol =1050 g

    [H+] &gt; [OH-]

    OH-

    HCl / Cl-

    [H+] = 10^-3 M

    [H+] = 10^-5 M

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