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Help me to figure out the equation?

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A ball is thrown down vertically with an initial speed of 25.5 m/s from the height of 78.5 m. What will be its speed just before it strikes the ground?

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  1. 26 mph.


  2. Sorry Gary not even close!

    Vf^2 = Vo^2 + 2 * g * h

    Vf^2 = (25.5)^2 + 2 * 9.8 * 78.5

    Vf^2 = 2189

    Vf = 46.8 m/s
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