Question:

Help me with logarithms equation?

by Guest11109  |  earlier

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2^(5x+1) = 2^(3x+2) + 2^3

solve for x.

Help me please.

Thanks a lot.

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  1. Log2^5x+1=Log2^3x+2+Log2^3  

       Log2^5x+1=Log2^(3x+2)*3=Log2^9x+6

    Log2^5x+1=log2^9x+6  =log 2 cut log2

    5x+1=9x+6  -4x=5    x=-5/4


  2. you dont have to solve it with logarithms. i think you just solve it like this 5x+1= 3x+2+3 and x=2 i think im not sure..
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