Help me with this math problem please?

Question

The directions are: "Label the origin and the x- and y-intercepts as O, P, and Q, respectively. Find the area of triangle OPQ."

The equation is: 3x - 2y = 6

Answer 1

Assuming the equation creates a triangle with the axes, we solve for the intercepts. (The origin O is (0,0)).

3x - 2y = 6

y-intercept (0,-3)

x-intercept (2,0)

so P is (0,-3) and Q is (2,0)

The area is base*height/2 = 3*2/2 = 3

The base and height are easily found as they are the values on the axes.

Hope this helps.

Answer 2

well, x intercept is 2 and y-int is -3 but i hav no clue about the rest!

Answer 3

i have no clue!

Answer 4

given equation is 3x - 2y = 6

label origin...as O

put x = 0 in equation  u get

2y =6

y=3

y intercept is 3

point is (0,3)

put y = 0 in equation

u get

3x=6

x=2

x-intercept is 2

point is (2,0)

label that points...

join (2,0) and(0,3)

u got a triangle........

hopes this will help u

Answer 5

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