Help me with this math problem????easy!!!?

Question

ok this is going to be easy for you older ppl cause its 7th grade level questions.so here they are-

1.)given the formula: F=9/5C +32.

convert 22 degrees Celsius to degrees Fahrenheit.

would you consider this temp. warm or cold?

2.)write 3 fractions that are less than 5/12 without using the same denominator more than once.

3.)given the following numbers,find their least common multiple (LCM)

16 20

4.)given the following numbers,find their greatest common factor(GCF)

16 20

Answer 1

1] ans is 71.6 F n dat cumz under warm temp.u cn figure it out frm d given temp in termz of celsius as 22 degree isnt dat kewl......bt moderate.

3] to tk out lcm write all d factors of d givn numbers n take out these numbers withe their max power.

16= 4X4= 2^2 X 2^2= 2^4

20=2 X2 X5=2^2  X 5

THEREFORE, LCM= 2 X 2 X 2 X2 X 5=16 X 5=80

4] HCF IS THE least commonfactor ie in dis case u hv 2 pik out the no. common to both with the least power

16=2^4

20=2^2 x 5

threfore, hcf= 2^2

note: 2 prime nos have 1 as their hcf as nuthin is common btw thm.

2]5/12=.41

ie u have 2 find out fractions witrh value less than .41

1/3=.3333=.34

2/5=.40

4/11=.36

2/7=.222

Answer 2

F=9/5(22) +32 = 71.6 degrees.   I would consider that wonderful (not too hot, not too cold) since I'm sitting in 100+ degrees in AZ.

9/24 ,14/36 , 2/6

80

4

Answer 3

1)  Just plug in the 22 degrees Celsius for the "C" in the equation:  F=9/5(22)+32  Now you can use a calculator to find "F"

2)  Three fractions that are less than 5/12 would be, let's say: 4/12, 3/12, and 2/12.  Since you can't use the same denominator more than once, you need to change the denominator on two of them without changing the value of the fraction.  To do this you simply need to multiply or divide the numerator and denominator by the same number.  For 3/12:  12 can be divided by three.  So 3/12 = 1/4  For 4/12:  12 can also be divided by 4 evenly.  So 4/12 = 1/3 because 12 divided by 4=3

3)  To find the LCM, first find the prime factors of each number.  16:  2, 2, 2, 2.  20:  2, 2, 5.  Then you multiply the each prime number the greatest amount of times it occurs in either number.  So the number 2 occurs 4 times in 16 and the number 5 occurs once in 20.  Now we multiply 2*2*2*2*5=80.  LCM=80

4)  To find the GCF, you need to list the prime factors of each number and then multiply the ones they have in common.  Prime factors of 16:  2, 2, 2, 2.  20:  2, 2, 5.  They both have 2 and 2.  So you would multiply 2*2=4.  GCF=4