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Help on algebra problem, forgot this over the summer.?

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find the equation of the line containing the following points. write the answer in standard form. (2, 6) and (4, 1)

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  1. What's da problem.


  2. First find the slope, which is

    difference in y

    ____________

    difference in x

    So slope = (1-6)/(4-2) = -5/2

    Now substitute into y = mx + b with one of the points to solve for b:

    6 = (-5/2)2 + b

    6 = -5 + b

    11 = b

    So the equation is y = -5x/2 + 11

  3. Use point/slope formula: y1-y2=m(x1-x2)

    slope (Derived from points):-5/2

    y-6=-5/2(x-2)

    y=-5/2x+11

  4. To do this, you'll need to find the slope first.

    Change in Y over change in X.

    1-6 = -5, and 4-2 = 2. So your slope is -5/2.

    Now, use the point-slope formula, for when you have a point or two on the line and a slope.

    y-y1 = m(x+x1)

    m meaning slope.

    We'll use the first point.

    y-6 = -5/2 (x-2)

    Distribute the -5/2 and move the -6 to the other side, and you'll get standard form: y=-5/2x + 11.

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